数极限 习题课
函数极限 习题课
典型例题 例1求lm 1+ tan x x→01+sinx 解解法讨论 设lm∫(x)=0,limg(x)=∞,则 lim(1+f(x)j8(x)=emg()In I#f(x) lim g(x)l+f(x)_ otlimg(x)f(x) 等价无穷小代换:n1f(x)~±f(x)
例1 ) . 1 sin 1 tan lim( 3 1 0 x x x x + + → 求 解 解法讨论 设 lim f (x) = 0,lim g(x) = ,则 ( ) lim ( )ln[1 ( )] lim[1 ( )]g x g x f x f x e = lim g( x)[ f ( x)] e = . limg( x) f ( x) e = 等价无穷小代换:ln[1 f (x)] ~ f (x)) 典型例题 "1 "