《理工科代数基础》补充题

01 01 =O 0 k 01 Jn(4) 故,当m,= 01 2(4)最大oam阶数时, (n(4)-Aln)=0

6 0 1 1 0 0 1 ( ) 1 0 0 1 1 0 i i i n i i n n J I       = −     0 1 1 0 k k O       =       ( ) ( ( ) ) i i i i i n i m n i i n m J Jordan J I O    = − = 故 当 的最大 的阶数时 ,

m()=(-2(-21)"…J-x.D) 2(42)-4y Ln(2)-47ny [(-n,In Jn(2)-2/n

7 1 2 2 1 2 1 1 [ ( ) ] [ ( ) ] s s m n n m n s n O J I J I         −   =     −   1 2 1 2 ( ) ( ) ( ) ( ) m m ms m J J I J I J I A s = − − −    2 1 1 2 3 3 1 2 3 2 [ ( ) ] [ ( ) ] m n n m n n J I O J I       −         −    