非结点荷载处理 q 6 q 2 5 q3 单元固端力 2= 单元等效结点荷载 t (Pe) a] [o Fh 广[1 LaleH
六.非结点荷载处理 ---单元固端力 e q q q e q F F F F = 3 2 1 Fq1 Fq2 Fq3 Fq4 Fq5 Fq6 e q e e PE = − T F ---单元等效结点荷载 = − q q e q T e E e E F F P P 2 1 2 1 0 0 − − = e q T e q T F F 2 1 e
例计算图示结构的等效结点荷载 2(4,5,6) (7,8,9)1 E2 1,2,3) 2l2 LPE {P点 P222 E {P P E力 +22 {P2」3 y=2
例.计算图示结构的等效结点荷载 2(4,5,6) 1(1,2,3) 3 (7,8,9) 1 2 P q l l / 2 l / 2 = PE = = 3 2 1 9 2 1 E E E E E E E P P P P P P P = 1 2 1 1 1 E E E P P P 3 2 2 1 3 2 1 1 E 1 P 1 PE 2 = 2 2 2 1 2 E E E P P P 2 1 2 1 = PE 3 2 1 1 E 1 P 1 PE 2 2 E 1 P 2 E 2 + P
例计算图示结构的等效结点荷载 2(4,5,6) q P/2 P/2 (7,8,9)1 Pl/8 P/8 1,2,3) 100 2l2 00 E PrH=-WFF E丿2 P/2 E P1/ Pl/8 Pl/8 P P1/ 8 P/2 P/2
例.计算图示结构的等效结点荷载 = 1 2 1 1 1 q q q F F F = /8 / 2 0 1 1 Pl Fq P 1 Pl /8 P Pl /8 P/ 2 P/ 2 − = /8 / 2 0 1 2 Pl Fq P = 0 = 0 0 1 0 1 0 1 0 0 1 − = − = − /8 / 2 0 1 1 1 1 Pl P Fq P T E = − /8 / 2 0 1 2 Pl PE P 2(4,5,6) 1(1,2,3) 3 (7,8,9) 1 2 P q l l / 2 l / 2 = PE 1 E 1 P 1 PE 2 2 E 1 P 2 E 2 + P
例计算图示结构的等效结点荷载 2(4,5,6) q4 l/2 q (7.9)1 qE2 1,2,3) l/2F=P/2 2l2 P/8 P|/8 q12/12a=90 E O10 [] 10O E o 0 1 =P2 l/2 E丿2 q}2/2 2/12 E几2 P/2 Pl/ 8
例.计算图示结构的等效结点荷载 2(4,5,6) 1(1,2,3) 3 (7,8,9) 1 2 P q l l / 2 l / 2 − = − = − /8 / 2 0 1 1 1 1 Pl P Fq P T E = − /8 / 2 0 1 2 Pl PE P = PE 1 E 1 P 1 PE 2 2 E 1 P 2 E 2 + P 2 /12 2 ql ql / 2 q /12 2 ql ql / 2 = 1 2 1 1 1 q q q F F F = /8 / 2 0 1 1 Pl Fq P − = /8 / 2 0 1 2 Pl Fq P = 90 = − 0 0 1 1 0 0 0 1 0 2 − = − = /12 0 / 2 2 2 1 2 1 ql ql P Fq T E = /12 0 / 2 2 2 2 ql ql PE
例计算图示结构的等效结点荷载 1/2 2(4,5,6) q2/12 (7,8,9)1 +ql/2 1,2,3) 2l2 ={P+ P/2+0 P/8+q2/2 E E }={H+2 P/2 E pl/8 =P2 l/2 E丿2 q}2/2 2/12 E几2 P/2 Pl/ 8
例.计算图示结构的等效结点荷载 2(4,5,6) 1(1,2,3) 3 (7,8,9) 1 2 P q l l / 2 l / 2 − = − = − /8 / 2 0 1 1 1 1 Pl P Fq P T E = − /8 / 2 0 1 2 Pl PE P = PE 1 E 1 P 1 PE 2 2 E 1 P 2 E 2 + P − = − = /12 0 / 2 2 2 1 2 1 ql ql P Fq T E = /12 0 / 2 2 2 2 ql ql PE − − + − + + − = / 8 / 2 0 / 8 /12 / 2 0 0 / 2 /12 0 / 2 2 2 Pl P Pl ql P ql ql ql = PE 1 E 1 P 1 PE 2 2 E 1 P 2 E 2 + P