0 年● 0 x=4 0 0 c,+(-1)C1 i=2,3,-n+1 x+24,)14,-a x-2 0 i=1 2-4143-2·X-m =(x+∑4，)x-4)(x-ar-a) i1 =(x+2a,-a) i=1 i=1
1 1 1 ( ) 2 1 2 2,3, 1 1 2 1 3 2 1 0 0 0 1 0 0 ( ) 1 0 1 i i c a c n i i n i n x a x a a a x a a a a a x a + − − = + = − ====== + − − − − − 1 2 1 ( )( )( )( ) n i n i x a x a x a x a = = + − − − 1 1 ( ) ( ) n n i i i i x a x a = = = + −
例6 1+1 1 1+2 1 计算D 1+3 (0≠0，i=1,2,.,n) 1 .11+0m元 [分析首行乘以（一1）加至2至n行可得箭形行列式 解1+41 1 1+4,+ 11.11 24 a, 0 0 0 9+4)e 0 20 .00 D= 03 .00 i=2,3,n 0 043.0 0 00 .00n 0 00.0元 i2
例6 计算 解: [分析]首行乘以(－1)加至2至n行可得箭形行列式 1 2 3 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ( 0, 1,2, , ) 1 1 1 1 1 i n a a D a i n a a + + = = + + = + = + + ===== 1 1 1 1 2 ( ) 2 2,3, , 3 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 i i n i i a c c a i n n a a a a a a + − = − − 1 1 2 1 3 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 n a a a D a a a a 1 2 3 1 1 2 2 1 1 (1 ) (1 ) n n n n i i i i a a a a a a a a = = a a = + + = +