带通抽样BAM)问题：m(t)如何不B= f-fL采样，既能保证fi >>B采样后信号频谱0fifn无混叠，又能有效利用带宽？s.(f)f,≥2fH0f、(M,(f)/
带通抽样 M f ( ) f H f L 0 f 0 f ( ) M f s B H L B = f − f f L B s H f 2 f 0 f ( f ) T s − f sf 问题：m(t)如何 采样，既能保证 采样后信号频谱 无混叠，又能有 效利用带宽？
带通抽样BAM(f)不B= fH-fLfi >>Bfa=nB,n是整数0fifHf, =2BSrCf0-ffM,(f)
12 0 f ( ) M f s 带通抽样 M f ( ) f H f L 0 f B H L B = f − f f L B 0 f ( f ) T s − f sf , H f nB n = 是整数 f s = 2B
带通抽样BAM(f)不B= fH-fLfi >>Bfa=nB,n是整数0fifHf,=2Bs.(f)0ffsM,(f)0
13 0 f ( ) M f s 带通抽样 M f ( ) f H f L 0 f B H L B = f − f f L B 0 f ( f ) T s − f sf f s = 2B , H f nB n = 是整数
带通抽样BM(f)不B= fH-fLfi >>Bfa=nB,n是整数0fifHJ, =2BSrCf0-f.f+M)C
14 0 f ( ) M f s 带通抽样 M f ( ) f H f L 0 f B H L B = f − f f L B 0 f ( f ) T s − f sf f s = 2B , H f nB n = 是整数
带通抽样BM(f)不B= fH-fLfi >>Bfa=nB,n是整数0fifHf,=2Bsr(f)0f.fM,(f)
15 0 f ( ) M f s 带通抽样 M f ( ) f H f L 0 f B H L B = f − f f L B 0 f ( f ) T s − f sf f s = 2B , H f nB n = 是整数