20KN/m100KN江蘇科技大学++++++++++Wjiangsu university of sclence and technologyEI-1BEI=2EI-1ATOT计算分配系数u:6m4m4m6m结点B:结点C:2= 0.667=4xSBA = 4iBAScB = 4iBc = 4×二682ScD = 3icp = 3×= = 0.54xSBc = 4iBc川860.66710.4=0.667EHBAμcB1+0.51+0.6670.510.6=0.333μCDμBC1±0.6671+0.521BC+UBA检查?1μcB +μUcDSchool of Civil Engineering and Architecture
School of Civil Engine School of Civil Engineering and Architecture ring and Architecture 2 计算分配系数μ: 0.6 1 0.667 1 0.4 1 0.667 0.667 1 8 2 4 4 0.667 6 1 4 4 BC BA BC BC BA BA S i S i B 结点 : 0.333 1 0.5 0.5 0.667 1 0.5 1 0.5 6 1 3 3 1 8 2 4 4 CD CB CD CD CB BC S i S i C 结点 : 检查 1 BC BA? 1 CB CD ? 20KN/m 100KN A B CD 6m 4m 4m 6m EI=1 EI=2 EI=1
江蘇科技大学20KN/m100KNjiangsu university of science and technology++++++力矩的分配传EI=1EI=2EI=1BAD递:O0.40d0.6000.667 0.333分配系数ABCD7TOT77-60-100600固端弯矩1000C一次分配传递-33.4-66.7-33.3022.0B一次分配传递14.729.444.0-7.3C二次分配传递-14.7-7.32.2B二次分配传递1.52.94.4-0.7C三次分配传递-1.5-0.7CB三次分配2.20.30.40.20-43.6杆端弯矩41.3 -41392.6-92.692.641343.60绘内力90200BAO21.90M图 (KN.m)133.1hoblof Civil Engineering andArchitecture
School of Civil Engine School of Civil Engineering and Architecture ring and Architecture 力矩的分配传 递: 3 20KN/m 100KN A B CD EI=1 EI=2 EI=1 C一次分配传递 -33.4 0 分配系数 0.400 0.600 0.667 0.333 固端弯矩 -60 60 -100 100 0 0 A B CD -66.7 -33.3 B一次分配传递 14.7 22.0 29.4 44.0 C二次分配传递 -7.3 -14.7 -7.3 0 B二次分配传递 1.5 2.2 2.9 4.4 C三次分配传递 -0.7 -1.5 -0.7 0 B三次分配 0.3 0.4 杆端弯矩 -43.6 92.6 -92.6 41.3 -41.3 0 0.2 2.2 A B C D 43.60 21.90 92.6 133.1 41.3 绘内力 90 200 图: 4 M图(KN.m)
江蘇科技大学jiangsu university of sclence and technology20KN/m【例8.3】51414IBCTOA导3I31T7E1E5m4m4m解求固端弯矩91220×42MF:40KN.mBA88ql?20×52MF-41.7KN·mBC121220x52q1?MF:41.7KN-mCB1212School of Civil Engineering and Architecture
School of Civil Engine School of Civil Engineering and Architecture ring and Architecture 【例8.3 】 解 : 1 求固端弯矩 KN m ql M KN m ql M KN m ql M F CB F BC F BA 41.7 12 20 5 12 41.7 12 20 5 12 40 8 20 4 8 2 2 2 2 2 2 20KN/m AB CD E F 4m 5m 4m 4m 2m 4I 5I 4I 3I 3I
江蘇科技大学jiangsu university of sclence and technology计算分配系数u:结点B:结点C:4EI5EIScB = 4ibc = 4x3EI4EISBA = 3iBA = 3x一545EI4EI=4EI=3EI= 4i BC=4×Scp = 3icp =3xS BC543EI3EI4x=3EIScF = 4icp =.4 x2EISBe =4iBc46μBA = 0.3μcB = 0.445μBC = 0.4μcD = 0.333μBE = 0.3μcF=0.222SchoolofCivilEngineeringandArchitecture
School of Civil Engine School of Civil Engineering and Architecture ring and Architecture 2 计算分配系数μ: 0.3 0.4 0.3 3 4 3 4 4 4 5 5 4 4 3 4 4 3 3 BE BC BA BE BC BC BC BA BA EI EI S i EI EI S i EI EI S i B 结点 : 0.222 0.333 0.445 2 6 3 4 4 3 4 4 3 3 4 5 5 4 4 CF CD CB CF CD CD CD CB BC EI EI S i EI EI S i EI EI S i C 结点 :
江蘇科技大学jiangsu university of sclence and technology力矩的分配传递:BABCCFBECBCD分配系数u0.30.30.40.4450.2220.333B41.740-41.7O固端弯矩-9.3-18.5-9.3-13.93.33.34.42.2-0.5-1.0-0.5-0.70.150.150.20. 1-46.943.43.524.5-9.8-14.6TEEBFC1.6-4. 70.1-0. 2TIE1.7-4.9School of Civil Engineering and Architecture
School of Civil Engine School of Civil Engineering and Architecture ring and Architecture 力矩的分配传 递: 3 AB C E F D -18.5 -9.3 -13.9 3.3 3.3 4.4 -1.0 -0.5 -0.7 0.15 0.15 0.2 EB 2.2 1.6 FC -9.3 -4.7 -0.5 -0.2 43.4 3.5 -46.9 24.5 -9.8 -14.6 1.7 -4.9 0.445 0.222 0.333 BA BE BC CB CF CD 分配系数μ 0.3 0.3 0.4 固端弯矩 40 -41.7 41.7 0.1 0.1