弯曲内力nternal forces in beamsF2dbaeCF3F一BCAEDP291aaaa122bdcaebdcea131215dbca291215-291)+122+-215)=-131kN·mMc2
6 (Internal forces in beams) 291 d a c b e 215 131kN m 2 1 291 122 2 1 MC = ( − ) + + ( − ) = − C B F2 F3 a D E F1 A a a a 122 + d a c b e 215 d a c b e 291 215 131 d a c b e
q解：①写出内力方程M(x)Q(x)= -qxQ(x)xM(x) =-qx2Q(x)x②根据方程画内力图qLqL?2xM(x)
解：①写出内力方程 ②根据方程画内力图 Q( x ) = −qx 2 2 1 M( x ) = − qx L q M(x) x Q(x) Q(x) x M(x) x – qL 2 2 qL − ⊕ ○