Chapter 8 Real gases
Chapter 8 Real Gases
Physical Chemistry Real gases Homework · Section8.2:8.2.8.3 Section84:8.7.8.11 Section85:8.17.8.18 Section87:8.20.8.21 Section 8.8 :8.26 · General:835.8.38.840.8.45
Homework • Section 8.2: 8.2, 8.3 • Section 8.4: 8.7, 8.11 • Section 8.5: 8.17, 8.18 • Section 8.7: 8.20, 8.21 • Section 8.8: 8.26 • General: 8.35, 8.38, 8.40, 8.45 Physical Chemistry Real Gases
Physical Chemistry Real gases Estimate a molar volume e Estimate the molar volume of CO 2 at 500 K and 100 atm by treating it as a van der Waals gas.(the van der waals e coefficients of co are: a=3.592 atmL2mo1-2 6=4267x10-2L mo Answer. Rearrange equation( 8.2) for a molar volume RT a V-b (8.2) RT ab 73-b+ 0 P RT(8.206×10- Latmk- mo)×(500K) 0.410LmO P 100atm
Estimate a molar volume Estimate the molar volume of CO2 at 500 K and 100 atm by treating it as a van der Waals gas. (the van der Waals coefficients of CO2 are: a=3.592 atmL2mol-2 , b=4.26710-2 L mol-1 ) Answer. 1 2 1 1 0.410 100 (8.206 10 ) (500 ) − − − − = = Lmol atm LatmK mol K P RT 2 (8.2) m Vm a V b RT P − − = Rearrange equation (8.2) for a molar volume 0 3 2 − = + − + P ab V P a V P RT Vm b m m Physical Chemistry Real Gases
Physical Chemistry Real gases Estimate a molar volume e Estimate the molar volume of CO 2 at 500 K and 100 atm by treating it as a van der Waals gas.(the van der waals e coefficients of co are: a=3.592 atmL2mo1-2 6=4267x10-2L mo Answer RT r2 arab P P RT(8.206×10- Latmk- mol)×(500K) =0.410LmOl 100atm RT 6+ 0453Lmo0=3.59×10(Zmo ab =1.53×10-3(Lmol)3
Estimate a molar volume Estimate the molar volume of CO2 at 500 K and 100 atm by treating it as a van der Waals gas. (the van der Waals coefficients of CO2 are: a=3.592 atmL2mol-2 , b=4.26710-2 L mol-1 ) Answer. 1 2 1 1 0.410 100 (8.206 10 ) (500 ) − − − − = = Lmol atm LatmK mol K P RT 0 3 2 − = + − + P ab V P a V P RT Vm b m m 1 0.453 − + = Lmol P RT b 2 1 2 3.59 10 ( ) − − = Lmol P a 3 1 3 1.53 10 ( ) − − = Lmol P ab Physical Chemistry Real Gases
Physical Chemistry Real gases Estimate a molar volume Answer RT r2 arab 2+ P RT(8.206×102 Latmk mol)×(500K) 0.410Lmol 100a RT 6+ =0.453Lmol1 3.59×10-2(Lmol) 1.53×10-°(/mol) Must solve Vn3-0.453V2+(359×102) (1.53×103)=0
Estimate a molar volume Answer. 1 2 1 1 0.410 100 (8.206 10 ) (500 ) − − − − = = Lmol atm LatmK mol K P RT 0 3 2 − = + − + P ab V P a V P RT Vm b m m 1 0.453 − + = Lmol P RT b 2 1 2 3.59 10 ( ) − − = Lmol P a 3 1 3 1.53 10 ( ) − − = Lmol P ab 0.453 (3.59 10 ) (1.53 10 ) 0 3 2 2 3 − + − = − − Vm Vm Vm Must solve Physical Chemistry Real Gases