引出点移动 2 H 2 3 a H
引出点移动 G1 G2 G3 G4 H3 H2 H1 a b G1 G2 G3 G4 H3 H2 H1 G4 1 请你写出结果,行吗？
综合点移动 向同类移动 H
G2 H1 G1 G3 综合点移动 G1 G2 G3 H1 G2 错！ 向同类移动 无用功 G1
作用分解 HI H3 H
G1 G4 H3 G2 G3 H1 作用分解 H1 H3 G1 G4 G2 G3 H1 H3
梅逊公式介绍RC C(s)_∑P△k R(S) △称为系统特征式 △=1-∑L+∑LbLe-∑LLLr+ 其中: ∑Ln所有单独回路增益之和 ∑LbL。所有两两互不接触回路增益乘积之和 de 所有三个互不接触回路增益乘积之和 Pk-从R(s)到C(s)的第k条前向通路传递函数 △称为第k条前向通路的余子式 △求法去掉第k条前向通路后所求的△ △=1∑LA+∑LBLc∑LLLr+
Pk—从R(s)到C(s)的第k条前向通路传递函数 梅逊公式介绍 R-C C(s) R(s) = ∑Pk△k △ : △称为系统特征式 △= 其中: —∑La 所有单独回路增益之和 ∑LbLc—所有两两互不接触回路增益乘积之和 ∑LdLeLf—所有三个互不接触回路增益乘积之和 △k称为第k条前向通路的余子式 △k求法: 去掉第k条前向通路后所求的△ - ∑La + ∑LbLc 1 -∑LdLeLf+… △k=1-∑LA+ ∑LBLC- ∑LDLELF+…
梅逊公式例R-C G4(s) R(s)→→Q sG(sHdG3(s)HTC( H(s}8 (s) △1=1 △2=1+G1H1 C(s) R(S) PIGG2G3 P2=G4G3 G1H,L=-G3 H G,GGaHH G Ls=-GG2G3LL2(G,H1)(G3H3)=G,G3H, H3 =(G1H1)(G4G3)=G1G3G4H1
R(s) C(s) L1= –G1 H1 L2= – G3 H3 L3= – G1G2G3H3H1 L4= – G4G3 L5 = – G1G2G3 L1L2= (–G1H1 ) (–G3H3 ) = G1G3H1H3 L1L4=(–G1H1 )(–G4G3 )=G1G3G4H1 G4 (s) H1 (s) H3 (s) G1 (s) G2 (s) G3 (s) G4 (s) H1 (s) H3 (s) G1 (s) G2 (s) G3 (s) G4 (s) H1 (s) H3 (s) G1 (s) G2 (s) G3 (s) G4 (s) H1 (s) H3 (s) G1 (s) G2 (s) G3 (s) G4 (s) H1 (s) H3 (s) G1 (s) G2 (s) G3 (s) G4 (s) H1 (s) H3 (s) G1 (s) G2 (s) G3 (s) G4 (s) H1 (s) H3 (s) G1 (s) G2 (s) G3 (s) G4 (s) H1 (s) H3 (s) G1 (s) G2 (s) G3 (s) G4 (s) H3 (s) G2 (s) G3 (s) G4 (s) H1 (s) H3 (s) G1 (s) G2 (s) G3 (s) G1 (s) G2 (s) G3 G1 (s) (s) G2 (s) G3 (s) G4 (s) H1 (s) H3 (s) G1 (s) G2 (s) G3 (s) G4 (s) H1 (s) H3 (s) G1 (s) G2 (s) G3 (s) G4 (s) G3 (s) 梅逊公式例R-C H1 (s) H3 (s) G1 (s) G2 (s) G4 (s) H1 (s) H3 (s) G1 (s) G2 (s) G3 (s) P1=G1G2G3 P2= G4G3 △1=1 △2=1+G1H1 C(s) R(s) =? 请你写出答案，行吗？