N2g)+3H2(g)-→2NH,(g) to:ng/mol 3.0 10.0 0 0 t1:ng/mol 2.0 7.0 2.0 51 t2:ng/mol 1.5 5.5 3.0 52 5=AmN2_2.0-3.0mol vN2) =1.0mol -1 $ △n2）_(7.0-10.0)mo1 v(H2) -3 =1.0mol △n,NH)_(2.0-0)mol v(NH) 2 =1.0mol 52=1.5mol
N (g) 3H (g) 2NH (g) 2 + 2 → 3 t0 : nB/mol 3.0 10.0 0 0 t1 : nB/mol 2.0 7.0 2.0 t2 : nB/mol 1.5 5.5 3.0 1 2 ( ) ( ) 1.0mol 1 (2.0 3.0)mol N N 2 1 2 1 = − − = = n 1.5mol 2 = ( ) ( ) 1.0mol 2 (2.0 0)mol N H N H 3 1 3 1 = − = = n ( ) ( ) 1.0mol 3 (7.0 10.0)mol H H 2 1 2 1 = − − = = n
5N,(g+H,(g)→NI,g) t=0 3.0 10.0 0 (mol) f= t 2.0 7.0 2.0 (mol) 5-An:1=(2.0-3.0)mol =2.0mol V(N2) -1/2 The extent of a reaction g must match the corresponding stoichiometric equation
The extent of a reaction ξ must match the corresponding stoichiometric equation. ( ) H (g) N H (g) 2 3 N g 2 1 2 + 2 → 3 ( ) ( ) 2.0mol 1/ 2 (2.0 3.0)mol 2 2 N ' N 1 = − − = = n 1 t = t 2.0 7.0 2.0 (mol) t = 0 3.0 10.0 0 (mol)
2.2 the First law of thermodynamics 2.2.1 Heat and work 2.2.2 Thermodynamic energy 2.2.3 the First law of thermo- dynamics
§2.2 the First law of thermodynamics 2.2.1 Heat and work 2.2.3 the First law of thermodynamics 2.2.2 Thermodynamic energy