202求: Rab例55QaOb52?20215Qba缩短无Qb电阻支路72152627926Q626242oa4SDaRab=10Q1527215232102
例5 求: Rab Rab ＝10 缩短无 电阻支路 15 20 b a 5 6 6 7 15 20 b 5 a 6 6 7 15 b a 4 3 7 15 b a 4 10
·例6计算902电阻吸收的功率12124Q92921029Q90220V90220V129210×90R10Q=1+ec10+9032104232i=20/10=2A3290220V10×292Q=0.2AE10+90P=90i =90×(0.2)2 =3.6W
• 例6 计算90电阻吸收的功率 10Ω 10 90 10 90 1 = + R eq = + i = 20/10 = 2A 0.2A 10 90 10 2 1 = + i = P = 90i 1 2 = 90(0.2) 2 = 3.6W 1 4 1 + 20V 90 9 9 9 - 9 3 3 3 1 4 1 + 20V 90 9 - 1 10 + 20V 90 - i1 i