己知P,求F F=P(1+i 期数 期初值 期末值 1 P F(1)=P+Pi=P(1+) 2 P(1+i F(2)=P(1+)+P(1+)=P(1+02 3 3 P(1+02 F(3)=P(1+1+P(1+)=P(1+)
已知P,求F 期数 期初值 期末值 1 P F(1) = P + Pi = P(1+i) 2 P(1+i) F(2) = P(1+i) + P(1+i) = P(1+I) 3 P(1+i) F(3) = P(1+i) + P(1+i) = P(1+I) . . . n 2 2 2 2 3 F = P(1+i)n
己知F,求P P=F*1/(1+i
已知F,求P P = F * 1 / ( 1+i ) n
已知A,求F A A A A A A A A 2 4 n-1 n
A A A A A A A A A • 1 2 3 4 n-1 n 0 已知A,求F 1 F t
已知A,求F 期数 F(n) 1 F(1)=A(1+0n-1 2 F(2)=A(1+)n-2 3 F(3)=A(1+0n-3 合计 F=A*[(1+0n-1]/1
已知A,求F 期数 F(n) 1 F(1) = A (1+i) 2 F(2) = A (1+I) 3 F(3) = A (1+i) . 合计 F = A * [ (1+i) -1 ] / i n-1 n-2 n-3 n