Created by Simpo PDF Creator Pro(unregistered version) hHn./hinimnondfoom R2+iX 3十 SLDe R2+iX2 AO S Si" S2' S2" S3' S3" jB1/2
Created by Simpo PDF Creator Pro (unregistered version) http://www.simpopdf.com S L D d A R1+ jX1 R2 +jX2 R3+ jX3 j B1/2 j B1/2 j B2/2 j B2/2 j B3/2 j B3/2 S L D b S L D c DQB1 S d R1+ jX1 R2 +jX2 R3+ jX3 j B1/2 b c d S b S c S1¢ S1² S2¢ S2² S3¢ S3² A
Created by Simpo PDF Creator Pro(unregistered version) h特nfh.n“imnondf om 从末段线路开始，用V依次计算各段线路的功率损耗 5=S ASL=((+S,=5+AS S;=5.+S,4S2=(21R2+X,hS2=3+4S N s=5+Sa5=(R+X,h5=9i+4S d AO ▣Mb Sr' S S2' S2" S3' S3" jB1/2 Se
Created by Simpo PDF Creator Pro (unregistered version) http://www.simpopdf.com S S S S , 1 1 1 1 1 1 2 1 ' 1 b 2 2 2 2 2 2 2 2 2 ' 2 c 3 3 3 3 3 3 3 2 3 3 L ' " N " L " L ' " N " L " L ' " N " d L ) ( R jX ), S S S V S S , S ( ) ( R jX ), S S S V S S S ( ) ( R jX ), S S S V S S S , S ( D D D D D D = + = + = + = + = + = + ¢¢ = = + = + 从末段线路开始，用VN依次计算各段线路的功率损耗 S d R1+ jX1 R2 +jX2 R3+ jX3 j B1/2 b c d S b S c S1¢ S1² S2¢ S2² S3¢ S3² A
Created by Simpo PDF Creator Pro(unregistered version) n卡s-hinssunimnn网6 nAW 用V和已求得的功率分布，从A点开始逐段计算电压降 落，求得V。、V.和Va AVa-PiR:+0X1.8V-PiX-2R V=VV4-4V尸+(V尸 4=P,+0,X2,6y=PX,-0 ', V.=V".-4VkP+(e尸 Mb Ri+X1 R2+jX2 Si" S2' S2" S3' S3 jB1/2 Se
Created by Simpo PDF Creator Pro (unregistered version) http://www.simpopdf.com 2 2 2 2 2 2 2 2 2 2 2 2 1 1 1 1 1 1 1 1 , , V ( V V ) ( V ) V P X Q R V V P R Q X V V ( V V ) ( V ) V P X Q R V V P R Q X V c c bc bc b ' ' bc b ' ' bc b A Ab Ab A ' ' Ab A ' ' Ab D d D d D d D d = - + - = + = = - + - = + = S d R1+ jX1 R2 +jX2 R3+ jX3 j B1/2 b c d S b S c S1¢ S1² S2¢ S2² S3¢ S3² A 用VA和已求得的功率分布，从A点开始逐段计算电压降 落，求得Vb、 Vc和Vd
Created by Simpo PDF Creator Pro(unregistered version) 含负荷变压器的计算 首先计算出对应高压侧的负荷功率，再求相应的运算功率 SD=SD+△S,+AS。 △心，=rR,+,),=+ 1.%s 100 △S0 SLDE SLpa
Created by Simpo PDF Creator Pro (unregistered version) http://www.simpopdf.com 含负荷变压器的计算 首先计算出对应高压侧的负荷功率，再求相应的运算功率 T T N N LD T LD LD T S I R jX S P j V S S S S S S 100 % ( ) ( ) , 0 0 0 2 0 ' D = + D = D + = + D + D T1 T2 T3 A b c d SLDb SLDc SLDd ’ ST S0 SLDd LDd S ¢