3.网络函数的应用②由网络函数求取任意激励的零状态响应R(s)→ R(s)= H(s)E(s)H(s)=E(s)例图示电路,i(t)=ε(t),l响应为u、u,求阶跃响应S(t)S,(t)22I (s)I(s)i(t)十2H122s3 U2(s)un(s)U.uiS1/4F爱图爱校XrznJhaoton西安交通大学求真理nvwy
3.网络函数的应用 ①由网络函数求取任意激励的零状态响应 ( ) ( ) ( ) E s R s H s = R(s) = H(s)E(s) 例 4/s 2s 2 1 I(s) U1(s) + + - - U2(s) I1(s) ( ) ( ) ( ) ( ) 1 2 S t S t i s t ε t u1 u2 求阶跃响应 、 图示电路, = ,响应为 、 , 1/4F 2H 2 i(t) u1 + + - - 1 u2
U,(s)解Ii(s)H(s)=I(s)I,(s)+2s3 U2(s)Ui (s)4s+44S1s2+5s+62+2sSU,(s)4s2sU,(s)H,(s)=I,(s)2+2ss2 +5s+ 64s+4U(s) = H(s)I(s) =s(s2 +5s +6)4sU,(s)= H,(s)I(s)s(s* +5s + 6)8S,(t) = 4e-t - 4e-3t3tS,(t) :3爱国爱校西安交通大学anJiaoton求真理nvwy
解 4/s 2s 2 1 I(s) U1(s) + + - -U2(s) I1(s) 5 6 4 4 2 2 1 1 4 1 ( ) ( ) ( ) 1 1 + + + = + + + = = s s s s s I s U s H s 2 S 5 6 4 2 2 2 ( ) ( ) ( ) ( ) 2 2 2 + + = + = = s ss s sU s I s U s H s 2 S ( 5 6 ) 4 4 ( ) ( ) ( ) 1 1 + + + = = s s s s U s H s I s 2 5 6 ) 4 ( ) ( ) ( ) 2 2 + + = = s(s ss U s H s I s 2 2t 3t 1 e 38 2e 32 S t − − ( ) = + − 2t 3t S2 t 4e 4e − − ( ) = −
②由网函数确定正弦稳态响应Ii(s)I(s)十2j03U.23 U2(s)U (s)4/S4/jo相量模型运算模型I(s)→iU(s)→U令:sL→joLjoc得: U, =H(jo)i U, =H,(jo)iH(s)中令s=jo得正弦稳态下的网络响应相量RR(jo)H(jo)=-E(jo)E激励相量爱国爱校西安交通大学XfinJictotong求真理tnveuwity
②由网函数确定正弦稳态响应 U s U I s I jωC 1 sC 1 sL jωL → → → → 令: ( ) ( ) 响应相量 激励相量 ( ) ( ) ( ) E j R j H j = E R = 4/s 2s 2 1 I(s) U1(s) + + - - U2(s) I1(s) 运算模型 相量模型 4/j 2j 2 1 + + - - U2 U1 1 I I H(s)中令s = jω得正弦稳态下的网络函数 U H jω I U H jω I : ( ) ( ) 得 1 = 1 2 = 2