辐射机理 贴片镯射器 地板上向半空间辐射 锁线 的两个缝隙 一抱饭 Patch 基片 {o) ￥A2 Radiating Radiating slot #1 slot #2 e Substrate Ground plane 辐射缝隙 L→ t Er h W Ground plane (c) C
UESTC 辐射机理 地板上向半空间辐射 的两个缝隙
薄介质假设 On patch and ground plane,E=0=2E (x,y) Inside the patch cavity,because of the thin substrate,the electric field vector is approximately independent of z. Hence E≈2E.（x,y) E.(x.y) h UESTC
UESTC 薄介质假设
Magnetic field inside patch cavity: H=-1 V×E j04 =-1V×(E,(x,》 jou =-a-2xvE(》 Hence x,川=0(2xE(x） UESTC
UESTC
Hx)=jon(xVE.(》 Note:the magnetic field is purely horizontal. (The mode is TM..) E（x,y) h 。1 (x,y) UESTC
UESTC
磁壁假设 On edges of patch, y J·2=0 Hence, W 以，=0 x L Also,on lower surface of patch conductor we have J=（-2×H) n h UESTC
UESTC 磁壁假设