上海交通大学：《现代控制理论》课程教学资源（讲稿）Chapter 3 Linear algebra

Chapter 3 7 6.Vector Function of Scalar f:R→R ( f5() f(t)= f(t) Furthermore,Vector Function of vector f:R"→R or (X) heory X X2 f(X)= (X) and X= L(x) m

6. Vector Function of Scalar n f : R  R or              ( ) ... ( ) ( ) ( ) 2 1 f t f t f t t n f Furthermore, Vector Function of vector m n f : R  R or              ( ) ... ( ) ( ) ( ) 2 1 X X X f X n f f f              m x x x ... 2 1 and X Chapter 3 7

Chapter 3 8 7.Matrix Function of Scalar Pu(t) P12(t) Pi(t) P:R→Ra P(t)= P21(t) P22(t) or P2m() … Pa(t)Pn2(1) Pnn()J」 Furthermore,Matrix Function of Vector Pu(X) P12(X) Pi(X) P:R'→R or P(X)= P21(X) P22(X) p2m(X) X= … P(X) P2(X) P(X) Example 2x1+3x22+hx3 f(X)= sin x +cos x3 where log x2 f(X)=2x1+3x,2+hx; x f2 (X)=sim x+cosx; and X= 2 f;(X)=log x2 X3

7. Matrix Function of Scalar n m R R  P :  or              ( ) ( ) ( ) ... ... ... ... ( ) ( ) ... ( ) ( ) ( ) ... ( ) ( ) 1 2 2 1 2 2 2 1 1 1 2 1 p t p t p t p t p t p t p t p t p t t n n n m m m P Furthermore, Matrix Function of Vector r n m R R  P :  or              ( ) ( ) ... ( ) ... ... ... ... ( ) ( ) ... ( ) ( ) ( ) ... ( ) ( ) 1 2 2 1 2 2 2 1 1 1 2 1 X X X X X X X X X P X n n n m m m p p p p p p p p p              r x x x ... 2 1 X Example               2 1 3 3 2 1 2 log sin cos 2 3 ln ( ) x x x x x x f X where 3 2 1 1 2 f ( X )  2 x  3 x  ln x 2 1 3 f ( X )  s in x  c o s x 3 2 f ( X )  lo g x and            3 2 1 X x x x Chapter 3 8

Chapter 3 9 8.Derivative of Matrix Function p11(t) dP0=P(0≌ p2(0… pim(t) dt p.2(t) Pnm(t)】 In a similar way ) df()-f0= f5(0) dt U 9.The gradient of f(X）f:R"→R af(x) Ox f(x) af(x) OX Ox2 Notations:Vf(X)or grad f(X)or f(x) Ox Example: 7 2X1 f(X)=f(x2 )=x2+sin x,+e" Then VI= ar coSX2 OX

8. Derivative of Matrix Function             ( ) ( ) ... ( ) ... ... ... ... ( ) ( ) ... ( ) ( ) ( ) 1 2 1 1 1 2 1 p t p t p t p t p t p t t d t d t n n n m m       P P In a similar way                  ( ) ... ( ) ( ) ( ) ( ) 2 1 f t f t f t t dt d t n    f f 9. The gradient of f ( X ) f R R n :                                n x f x f x f f ( ) ... ( ) ( ) ( ) 2 1 X X X X X Notations: or or  f ( X ) g r a d f ( X ) X f Example: 3 2 2 1 3 2 1 ( ) ( ) sin x x x e x x x f f              X  Then                3 2 1 cos 2 x e x x f f X Chapter 3 9

Chapter 3 10 f(X1,x2,xm） (X) 10.Jacobian matrix of f(X)= f2(X1:X2...xm) f5(X) fn(x1,x2xm） L(x) of 所 x2 of(x) 8 站 aX 0x2 xm ● a前 8x1 x2 Example: 2 f(X)=f( +X2-X4 sin x2 -X3 cory the Jacobian matrix is of 0 -3x,2 OX 0 c0sx2-10

10. Jacobian matrix of                           ( ) ... ( ) ( ) ( , ,... ) ... ( , ,... ) ( , ,... ) ( ) 2 1 1 2 2 1 2 1 1 2 X X X f X n m n m m f f f f x x x f x x x f x x x m n m n n n m m x f x f x f x f x f x f x f x f x f                                           ... ... ... ... ... ... ... ( ) 1 2 2 2 2 1 2 1 2 1 1 1 X f X Example:                        2 3 3 2 4 2 1 4 3 2 1 sin ( ) ( ) x x x x x x x x x f X f 4 2 f : R  R the Jacobian matrix is            0 cos 1 0 2 1 0 3 2 2 1 4 x x x X f Chapter 3 10

Chapter 3 11 11. Derivative of row vector function (X) 0(X)=[9(X),(X),…,0(X] 80 0p2 a中n x1 Ox1 O o(X) op 042 a中n OX 0x2 0x2 0x2 oo a4, op 0Xm xm Example:If X =[x.x]then OX OXT c⊙y -=I where I is a identity matrix

11. Derivative of row vector function φ ( X ) [ ( ) , ( ) , , ( ) ]  ( X )   1 X  2 X   n X m m n n m m n n x x x x x x x x x                                                     ... ... ... ... ... ... ... 1 2 2 2 2 2 1 1 1 2 1 1 X (X) Example: If then T m [ x , x , , x ] X  1 2  I X X X X       T where I is a identity matrix. Chapter 3 11