xin]=xa(tent=xa(nT) EXAMPLE Sampling the analog waveform 32m 256 samples (b) Figure 2.2
7 Figure 2.2 EXAMPLE Sampling the analog waveform x[n] x (t)| x (nT) = a t=nT = a
Basic Sequence Operations ◆ Sum of two sequences xn+yln Product of two sequences x{n]·y{n] Multiplication of a sequence by a numbera a·x[m] Delay(shift) of a sequence n=xIn-n 0· Integer 8 2/2/2021 Zhongguo Liu_ Biomedical Engineering_shandong Univ
8 2/2/2021 Zhongguo Liu_Biomedical Engineering_Shandong Univ. ◆Sum of two sequences ◆Product of two sequences ◆Multiplication of a sequence by a numberα ◆Delay (shift) of a sequence Basic Sequence Operations x[n]+ y[n] [ ] [ ] :integer n n0 n0 y n = x − x[n] y[n] x[n]
Basic sequences ◆ Unit sample sequence 0n≠0 (discrete-time impulse =0 impulse) Unit sample 0 2/2/2021 Zhongguo Liu_ Biomedical Engineering_shandong Univ
9 2/2/2021 Zhongguo Liu_Biomedical Engineering_Shandong Univ. Basic sequences ◆Unit sample sequence (discrete-time impulse, impulse) = = 1 0 0 0 n n n
Basic sequences 4-20134568 2 A sum of scaled delayed impulses p以]=a3n+3]+aoln-1]+a2|n-2]+a, ◆ arbitrary 对=∑k1[m=k] sequence k 2/2/2021 Zhongguo Liu_ Biomedical Engineering_shandong Univ
10 2/2/2021 Zhongguo Liu_Biomedical Engineering_Shandong Univ. Basic sequences =− = − k x[n] x[k] [n k] ◆arbitrary sequence 3 1 2 7 p n = a−3 n + + a1 n − + a2 n − + a7 n − A sum of scaled, delayed impulses
Basic sequences 1n≥0 Unit step sequence un 0n<0 nit step 0.1hen<0 =∑与 1n≥0 k≠0 k since d k=0 lm=8n]+8n-11+6m-2]+…=∑8[n-k1 fn]=u[n]-un-l First backward difference 2/2/2021 Zhongguo Liu_ Biomedical Engineering_shandong Univ
11 2/2/2021 Zhongguo Liu_Biomedical Engineering_Shandong Univ. Basic sequences ◆Unit step sequence = 0 0 1 0 [ ] n n u n =− = n k u[n] k = = + − + − + = − 0 [ ] [ ] [ 1] [ 2] [ ] k u n n n n n k [n] = u[n]−u[n −1] First backward difference 0, 0 , 1, 0 0 0 1 0 since n k when n k when n k k k =− = = =