第二章习题 213(2)每个象素色度所含的信息量为 H(Y)=log30=4.91 亮度和色度彼此独立 H(XY=H(X+H(Y=log 10+log 30=8.23 H(Xr) log=2.5 H(X log 10
第二章习题 2.13 (2)每个象素色度所含的信息量为： H Y( ) log 30 4.91 = = 亮度和色度彼此独立 ( ) ( ) ( ) log10 log 30 8.23 ( ) log 300 2.5 ( ) log10 H XY H X H Y H XY H X = + = + = = =
第二章习题 2.18(1)是平稳的 (2)H(x)=H(04)=-04l0g04+060g06)=097 H(X2)=2H(X)=2×0.97=1.94 H(X3X1X2)=H(X3)=H(X)=097 lim H,(X=H(X)=0.97 N→∞ (3)H(X2)=2H(X)=4×097=388 0000,0001,0010,0011,0100,0101,0110,0111 1000,1001,1010,1011,1100,1101,1110,1111
第二章习题 2.18 (1)是平稳的 (2) 2 H X H X ( ) 2 ( ) 2 0.97 1.94 = = = H X H ( ) (0.4) (0.4log 0.4 0.6log 0.6) 0.97 = = − + = 3 1 2 3 H X X X H X H X ( / ) ( ) ( ) 0.97 = = = lim ( ) ( ) 0.97 N N H X H X → = = (3) 2 H X H X ( ) 2 ( ) 4 0.97 3.88 = = = 0000,0001,0010,0011,0100,0101,0110,0111 1000,1001,1010,1011,1100,1101,1110,1111
第二章习题 2.22(1)Q(E)=P P(0)=pP(0)+P(1)+P(2) P(1)=pP(1)+P(0 )+P(2) P(2)=pP(2)+P(1)+P(0) 解得 (0)=P(1)=P(2)
第二章习题 2.22 (1) (0) (0) (1) (2) 2 2 (1) (1) (0) (2) 2 2 (2) (2) (1) (0) 2 2 p p P pP P P p p P pP P P p p P pP P P = + + = + + = + + ( ) ( ) Q E P a i i = 1 (0) (1) (2) 3 P P P = = = 解得：
第二章习题 222(2) H2=H2=∑QE,)H(X/E) =P(OH(X/0)+P(1)H(X/1)+P(2)H(X/2) 3*H(p =(plog万-2*P1nP 322 -plog p-pIog (3):H(X)=log3=1.585
第二章习题 2.22 (2) 3 2 1 ( ) ( / ) (0) ( / 0) (1) ( /1) (2) ( / 2) 1 3* ( , , ) ( log 2* log ) 3 2 2 2 2 log log 2 i i i H H Q E H X E P H X P H X P H X p p p p H p p p p p p p = = = = + + = = − − = − − （3）： H X( ) log 3 1.585 = =