N2(g+3H,(g)→2NH,(g) 5 to:ng/mol 3.0 10.0 0 0 ng/mol 2.0 7.0 2.0 5 2:ng/mol 1.5 5.5 3.0 52 5=△mN_(2.0-3.0)mol =1.0mol v(N2) -1 △n(2)_(7.0-10.0)mol v(H2) -3 =1.0mol 51= △n,(NH3)_(2.0-0)mol =1.0mol v(NH3) 2 52=1.5mol l
N (g) 3H (g) 2NH (g) 2 + 2 → 3 ξ t0: nB/mol 3.0 10.0 0 0 t1: nB/mol 2.0 7.0 2.0 t2: nB/mol 1.5 5.5 3.0 ξ 1 ξ 2 ( ) ( ) 1.0mol 1 (2.0 3.0)mol NN2 1 2 1 = −− = Δ = ν ξ n 1.5mol ξ 2 = ( ) ( ) 1.0mol 2 (2.0 0)mol NHNH3 1 3 1 = − = Δ = ν ξ n ( ) ( ) 1.0mol 3 (7.0 10.0)mol HH2 1 2 1 = − − = Δ = ν ξ n
)N,e)+H,g)→N,g) t=0 3.0 10.0 0 (mol) t=t 2.0 7.0 2.0 (mol) 5=Am,=(2.0-3.0)mol =2.0mol V(N2) -1/2 The extent of a reaction s should match the corresponding stoichiometric equation
The extent of a reaction ξ should match the corresponding stoichiometric equation. ( ) H () () g NH g 2 3 N g 2 1 2 + 2 → 3 ( ) ( ) 2.0mol 1 / 2 ( 2.0 3.0 )mol 2 2 N ' N 1 = − − = Δ = ν ξ n 1 t = t 2.0 7.0 2.0 (mol) t = 0 3.0 10.0 0 (mol)
2.2 the First law of thermodynamics 2.2.1 Heat and work 2.2.2 Thermodynamic energy 3=2.2.3 the First law of thermo- dynamics
§2.2 the First law of thermodynamics 2.2.1 Heat and work 2.2.3 the First law of thermodynamics 2.2.2 Thermodynamic energy