在水溶液中,K=[ H3oIIOH-I=1.0×1014 IH3O→|OH OHT lH3of 酸性溶液中,[OH≠0 碱性溶液中,[H3O]≠0
在水溶液中，Kw = [H3O+][OH-] = 1.0 × 10-14 [H3O+] [OH-] [OH-] [H3O+] 酸性溶液中， [OH-] ≠ 0 碱性溶液中， [H3O+] ≠ 0
The pH scale o The concentration of the hydrogen ion expressed as [H3o+l, is typically expressed in terms of pH pH =-log1o[ H3O+] ● pH interva:0-14 e pH changes by 1 for every power of 10 change in [H3O+]
The pH Scale The concentration of the hydrogen ion, expressed as [ H 3 O + ], is typically expressed in terms of pH. pH = − log10 [ H 3 O + ] pH interval: 0-14 pH changes by 1 for every power of 10 change in [ H 3 O + ]
pH Scale At25°c,apH of 7 is neutral 0 14 acid ba ase
pH Scale 0 7 14 acid base At 25 °C, a pH of 7 is neutral
Derivation Kw=[H3O+OH]=1.0×1014 log10(H3O+IOH])≡log1(1.0×1014) lO910 [H3O+]+log10[OH]=-14 -pH+(-pOH)=-14 pH pOH 14
19 Derivation K w = [ H 3 O + ][ OH − ] = 1.0 x 10-14 log10 ([ H 3 O + ][ OH − ]) = log10 (1.0 x 10-14 ) log10 [ H 3 O + ] + log10 [ OH − ] = −14 − pH + ( − pOH) = −14 pH + pOH = 14
★强酸HX(如:HCI)的水溶液 Hx(ag)+H2O①)→H3O’(ag)+x(ag) HX HX HaO()+ HaO()= HgO"(aq)+OH (aq) H3o=CHx+x IoH-=x K [H O*=CHx + x =chx +oh-1=cHx [H,o] 1H3o-CHxIH3O -Kw=0 ⅢH3O=(C HX +√Chx+4K)
[H O ] K 3 w + Ì 强酸 HX（如：HCl）的水溶液 [H3O+] = CHX + x [OH-] = x [H3O+]=CHX + x = CHX + [OH−]=CHX + [H3O+]2 − CHX[H3O+] − Kw = 0 [H3O+]= (C C 4K ) 21 w 2 HX + HX +