The equilibrium constant Ko Definition:K=Jp)equilibrium-=I(PB/pO )Vequrium Because△，G"m=fTD, So K0=f(T)---only related to the temperature. PDF文件使用"pdfFactory Pro”试用版本创建m,fineprint.com,cn
The equilibrium constant K0 f f Definition：K0 =(JP )equilibrium =Õ(PB /P0 ) nB equilibrium Because DrG0 m =f(T), So K0= f(T)---only related to the temperature. PDF 文件使用 "pdfFactory Pro" 试用版本创建 ÿwww.fineprint.com.cn 2
Note: .Ko is related to the expression of chemical reaction. 1/2N2+3/2H2→NH3 K N2t3H2→2NH3 1≠K2 2=(K)2 PDF文件使用"pdfFactory Pro”试用版本创建wmm,fineprint.com,cn
Note: •K0 is related to the expression of chemical reaction. 1/2N2+3/2H2ÞNH3 K0 1 N2+3H2Þ2NH3 K0 2 K0 1 ¹K0 2 K0 2=(K0 1 ) 2 PDF 文件使用 "pdfFactory Pro" 试用版本创建 Ìwww.fineprint.com.cn
The relation between J and Ko △，Gm=AGm+R7nnJr =-RTInK0+RTInJp SoJp≤K0 △，Gnm<0 the forward reaction is spontaneous.. Jp=K0 △，Gm=0 the reaction is at equilibrium. Jp>KO △，Gm0 the reverse reaction is spontaneous, PDF文件使用"pdfFactory Pro”试用版本创建m,fineprint.com,cn
The relation between JP and K0 DrGm =DrG0 m +RTlnJP = -RTlnK0 +RTlnJP So JP<K0 DrGm <0 the forward reaction is spontaneous. JP =K0 DrGm =0 the reaction is at equilibrium. JP>K0 DrGm >0 the reverse reaction is spontaneous. PDF 文件使用 "pdfFactory Pro" 试用版本创建 Ìwww.fineprint.com.cn
The relation between equilibrium constants .Ko and Kc 0-k2c28 PB-BRTIV-CBRT-(CB/CO)CORT -男9-学产y ·Kec=f刀--only related to the temperature.. PDF文件使用"pdfFactory Pro”试用版本创建mm,fineprint.com.cn
The relation between equilibrium constants •K0 and K0 C å =Õ =Õ = = = = å = B P C RT C B K C P C RT B C B B P B P B K C C RT B RT C B RT V C B n B P B P C RT C K K n n n n ) 0 0 ) 0 ( 0 0 0 ) ( 0 0 ( / ( / 0) 0 ) 0 0 0 0 ( • K0 C =f(T) ---only related to the temperature. PDF 文件使用 "pdfFactory Pro" 试用版本创建 ÿwww.fineprint.com.cn