Edge Dislocation 0x工 Try 0 9 y Oyy 0 0 00z2 a 0x Gb y(3x2+y2) Gb sin0(2+cos(20)) 2T(1-0(x2+y2)2 2π(1-V)） Ow= Gb y(22-y2) Gb sin 0.cos(20) 2x(1-0)(x2+92)2 2m(1-V) O2:=v(Oxz +Oyy) Gb x(x2-y2) Gb cosθcos(28) 0y=Txy=2r(1-(2+y2)2 -2r(1-)
Edge Dislocation Edge Dislocation
位错的弹性能 T()= G 1 2r(1-)x Fr =Tsy'L.da= G 2r(1-）x (a) da ro Ro Gb2 dx 10 Ro ro △x-b ()
位错的弹性能
位错的总性能 For an assessment of the radial size of the dislocation core ro,one can utilize the fact that the elastic stresses can never exceed the theoretical shear stress Cb T(ro)= 兰Th兰 2 T0≈b Ecore 2 m- Gb2 Gb2 2G 2元 8元 兰 4π(1-) The total energy per unit length of an edge dislocation is 9-号+受=(%+ a screw dislocation E(d兰 1 E(= 器（+1）
For an assessment of the radial size of the dislocation core ro,one can utilize the fact that the elastic stresses can never exceed the theoretical shear stress 位错的总性能
位错的相互作用 F12=(o1b2)×s2 If dislocation 1 intersects the origin of the coordinate system and extends parallel to the z direction,then s=[001]and bi =b2 =6[100]we obtain F12 周--- -0zzb 0 Gb2 cos0 cos(20) 2π(1-)） T
位错的相互作用
位错的相互作用 Gb2 cos0 cos(20) Boundary 2r(1-V) D=b/8 Grain 1- Grain 2 g
位错的相互作用