= mR-m(R2 -2Rr +r)+r'm=2mR0m independent ofgW=2RAnother interestingproblem:What is the behavior of lQas water leak off?Your classmates areg20your good teacher!1
mR m R Rr c r c r c m 2 2 2 2 = − ( − 2 + ) + 2 = 2mR R g w 2 2 = Another interesting problem: independent of •• What is the behavior of as water leak off? l l g = 2 Your classmates are your good teacher!
Related example about simple harmonic motionF(1)(2).mg(3).Potentialf =-kEu'(E) ocEu(5) ==kx? + Bx3 ..口2
Related example about simple harmonic motion k mg I o F (1). (2). (3). Potential f = −k u'() = + 2 3 2 1 u( ) k x x
1-2 Solution E(t)= = Acos(ot + Po)5+025=0Guess!= = Bsin( t + Po) A →amplitude (Period T=_ 2元 )0の frequencyPo initial phaseCiAcos(ot + Po) + C2 B sin( ot + Po)Complex number: real,imagineAei(ot+Po)Not physical quantity
0 2 + = •• cos( ) = +0 A t sin( ) = +0 B t cos( ) sin( ) 1 +0 + 2 +0 C A t C B t 2 T = ( ) 0 i t + Ae 1-2 Solution (Period ) frequency Guess! A amplitude 0 initial phase Complex number: real,imagine. Not physical quantity. (t)
i(ot+PoAt beginning it was used for convenience inAequantum mechanics ,it is necessary!Normal mode(2)
( ) 0 i t + Ae At beginning it was used for convenience in quantum mechanics ,it is necessary! Normal mode: (1). (2)
intrinsicA, @。 alter mined by initial condition50tan Po =t=05.=?一5.=AcosP050t=05.=? → 50 =-Aosin oEnergy:1 kA? cos?(ot + Po)1Ep22mA?? sin ?(ot + Po)Ekmy22
t = 0 ? 0 = 0 0 = Acos 0 0 0 tan • = − 0 2 0 0 • A = + 0 0 = −A sin • 0 = ? • t = 0 intrinsic. A, alter mined by initial condition. Energy: cos ( ) 2 1 2 1 0 2 2 2 Ep = k x = k A t + sin ( ) 2 1 2 1 0 2 2 2 2 Ek = m v = m A t +