F.Synchro friction coefficient pFul2β=FAF, = Fu +Fu442l(full load)Fu=βF1@o fullFru2 =(1- β)FμI(em pty load)FBDOemptyulF1-βu2ul1l
F 2 F1 I ( ) full load 0 full F F F F F F F F F (1 ) 2 1 1 2 1 1 2 1 F F 0 S y n c h r o f r i c t i o n c o e f f i c i e n t I ( e m p t y l o a d ) 0 em p ty 11
Note1) Po is determined by three factors which are L , theposition of mass center and β2) The position of mass center could be calculated by thefront and rear axle load.3) Different vehicles have their own different Po4) Each vehicle has its own two different os derived fromthe diversity of full load status and empty vehicle status.5) Po fuly-loadea > Po(lighib-ioaded because of :[bafiu)<b(empty)(>)hg(full)g(empty)12
1）φ0 is determined by three factors which are L , the position of mass center and β. 2）The position of mass center could be calculated by the front and rear axle load. 3）Different vehicles have their own different φ0 . 4）Each vehicle has its own two different φ0 s derived from the diversity of full load status and empty vehicle status. 5） 0( fullyloaded) ＞0(lightlyloaded) because of ： ( ) ( ) ( ) ( ) ( ) full empty g full g empty b b h h ＜ ＜＞ Note 12
5.Frontandrearlockupline clustersf线组&r线组(l"f"lineclusterDefinition:"f"describes the relationship between front andrear brake forces given by the ground (Fxb2~Fxbi) whenfront lockupoccursfirst.GH(b+zhZ1gLCGzha一Fxh2F6aZ2gXb1FnL1今13
（1）”f” line cluster Definition: “f “ describes the relationship between front and rear brake forces given by the ground (FXb2~FXb1) when front lockup occurs first. 5.Front and rear lockup line clusters f线组 & r线组 FZ1 FZ2 FXb1 FX 2b G g h Fj L a b 1 2 ( ) ( ) Z g Z g G F b zh L G F a zh L 13
How to get “f' ?Step:I) To get the relationship between Fxbi and Fxb2> becausefront lockup occurs firstFxbl = Fp1 = FzipFxb1 = (Gb + Gzh)G duF. Gz =Fxb1 + Fxb2g dtLFxb1 = Gb+ Fxb1 - hg + Fxb2 - hgSL-βhGbtherelationshipFFDXb2Xb1betweenFxbrandFngph.Xb2g14
Step: 1) To get the relationship between FXb1 and FXb2 because front lockup occurs first 1 1 1 1 ( ) Xb Z Xb g F F F F Gb Gzh L How to get “f” ? the relationship between FXb1 and FXb2 1 2 1 1 2 Xb Xb Xb Xb g Xb g G du Gz F F g dt L F Gb F h F h 2 1 g Xb Xb g g L h Gb F F h h 14
2)To Plot the relationship on a graphF xb2Making each “f" line with a different “"o0.20=0.10.30.50.4F xblclustersFGbp=0xbjFxb1Gb(1)(2)L-phGbF(0, -xb2hF=0n8xb215
FXb1 FXb2 g (0, ) Gb h ”f” clusters 0 . 1 0.2 0.3 0.4 0.5 2)To Plot the relationship on a graph 0 (2) 0 (1) 2 1 2 1 xb g xb g xb xb F L h Gb F h Gb F F Making each “f” line with a different “ φ ” 15