西安石油大学电子工程学院：《自动控制理论 Modern Control System》精品课程教学资源（英文PPT课件）Time-Domain Analysis Of Control System

Unit-step response: LetR(s)=1/s.Then Y s Ds+ K 2 +2S@,s+@m s y(6=1-e", sin (a,Bt+e) 1-e s 'sin(@ t+0 (3-3-10 where 0=c012B=-s0<5<1 2 (3-3-11) 2022-2-3

2022-2-3 11 Unit-step response: Let Rs  1 s . Then   2 2 2 2 1 1 2 n n n K Y s s ps K s s s s                  1 1 sin 1 1 sin n n t n t d y t e t e t                  , , , 2   1 1  cos    0    1 2 1 d  n   n  (3-3-9) (3-3-10) (3-3-11) where

jo, V1-22 0= cos 25o 2022-2-3

2022-2-3 12

Unit-impulse response: Let R(s)=1.Then K Y(S s+ ps+ K s+ cast a (3-3-12) where z=p/2√K K hence y(t=ne so sino,t (3-3-13) 2022-2-3 13

2022-2-3 13 Unit-impulse response: Let R  s   1 . Then   2 2 2 2 n n n K Y s s p s K s s          n  K   p 2 K   sin n n t d y t e t       where hence (3-3-12) (3-3-13)

=0.10 0.8 0.25 0. 0.50 0.4 0.2 yO 0.0 0.2 0.6 0.8 01234 678910 2022-2-3 14

2022-2-3 14

Standard performance measures for the second-order system are defined by using unit-step response as shown below Overshoot 1.0+6 1.0 二二一 二一 0.9 0-6 0.1 Time T Peak Settling tim tIme Rise time 2022-2-3 15

2022-2-3 15 Standard performance measures for the second-order system are defined by using unit-step response as shown below