85.16 Dis location in FCC crystals I Per fect dis locat ion b=na。+n2b+n2c For FCC b=-<110> Glide plane Burgers tor b o b a b o
§5.16 Dislocation in FCC crystals ◆ Ⅰ.Perfect dislocation b n a n b n c = 1 + 2 + 2 = 110 2 1 For FCC b
[10]→>=[211]+-[121
[121] 6 1 [211] 6 1 [110] 2 1 → +
II. Shock ley partial dislocation B C A b=-[101 The slip movement of a perfect dislocation consists of two steps, This can be expressed in terms of vector combination:11011=121+(2111
◆ Ⅱ.Shockley partial dislocation C A B [101] 2 1 b = The slip movement of a perfect dislocation consists of two steps, This can be expressed in terms of vector combination: [211] 6 1 [112] 6 1 [101] 2 1 = +
The Shockley partial is the line of demarcation on slip plane [111 between slipped and unslipped zones, the slip vector being<112> It also the boundary line between faulted and unfaulted zones
The Shockley partial is the line of demarcation on slip plane {111} between slipped and unslipped zones, the slip vector being . It also the boundary line between faulted and unfaulted zones. 112 6 1
[110 001 未滑001 已滑 - 4。404-c B B→C 112 FCC{111<112> BCC{112}<111 HCP{012}<1011>
FCC {111}<112> BCC {112}<111> HCP {1012}1011 A C B A C A C B A C B A C [110] [001] [110] [112] 2 1 [001] 未滑 已滑