·另解 P dna v dp pa dl n RT dt t dt RT dt D、HRT dv RT dn dt P dt n=no+Snox=no+o(n dh dh dt dt d rT dn dt p dt dn v dp dt RT dt 中p dt P RT(1+424) dt P(1+ t n40(1+2xA)φAn0(1+2xA)2 P(1+2 dt 3P dt 1+2x
• 另解： dt dp P n x dt dp x x P n x dt dp P p P n dt dp P p R T V dt dn dt dn P p dt dp R T V dt dn dt dn P R T dt dV dt dn dt dn n n n x n n n dt dn P R T dt dV P nRT V dt dV R T p dt dp R T V dt dn R T p V n A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A + = + − + + = + = + = = − = − = − = + = + − = = = = + 3 (1 2 ) ) 1 2 1 (1 2 (1 2 ) (1 ) (1 ) ( ) 2 0 0 0 0 0 0
③ dh Pa=y dt P dt =1×(-2.4)=0.1 dt 3
–③ = ? dt dyA 1 ( 2.4) 0.8 3 1 1 − = − = − = = s dt dy dt dp dt P dy p y P A A A A A