2.7 real gas Joule- Thomson experiment Joule在1843年所做的气体自由膨胀实验是不够精 确的,1852年 Joule和 Thomson设计了新的实验,称为 throttling process 在这个实验中,使人们对实际气体的U和H的性质 有所了解,并且在获得低温和气体液化工业中有重要 应用。 4上一内容下一内容◇回主目录 返回 2021/2/21
上一内容 下一内容 回主目录 返回 2021/2/21 2.7 real gas Joule-Thomson experiment Joule在1843年所做的气体自由膨胀实验是不够精 确的，1852年Joule和Thomson 设计了新的实验，称为 throttling process。 在这个实验中，使人们对实际气体的U和H的性质 有所了解，并且在获得低温和气体液化工业中有重要 应用
throttling process The Joule- Thomson expansion压缩区多膨胀区 consists of allowing a gas to expand through a porous plug P, V, T from a region of higher 焦耳一汤姆逊实验(1) pressure to a region of lower pressure as depicted in Fig 压缩区 多孔塞 膨胀区 pA The process is carried out steadily and adiabatically 焦耳一汤姆逊实验(2) 4上一内容下一内容◇回主目录 返回 2021/221
上一内容 下一内容 回主目录 返回 2021/2/21 throttling process The Joule-Thomson expansion consists of allowing a gas to expand through a porous plug from a region of higher pressure to a region of lower pressure as depicted in Fig. The process is carried out steadily and adiabatically
throttling process 压缩区多孔塞膨胀区压缩区 多孔塞‖膨胀区 P 焦耳一汤姆逊实验(1) 焦耳一汤姆逊实验(2) When the flow is sufficiently slow, the gas has well defined pressure and temperature on both sides of the restriction 4上一内容下一内容令回主目录 返回 2021/2/21
上一内容 下一内容 回主目录 返回 2021/2/21 throttling process When the flow is sufficiently slow,the gas has well defined pressure and temperature on both sides of the restriction
U and in the throttling process adiabatic 2 =0, then U7,-U1=△=W Left, Surroundings compresses gaseous system work, system got P1△=P1(△=0-1=-1) Right gaseous system expansion: work surr got 2=-P2△=-P2V2(△V=12-0=12) 4上一内容下一内容◆回主目录 返回 2021/2/21
上一内容 下一内容 回主目录 返回 2021/2/21 U and H in the throttling process W p V 1 1 = − Left, Surroundings compresses gaseous system: work, system got： Adiabatic Q=0 ，then： U U U W 2 1 − = = Right, gaseous system expansion： work , surr. got: W p V 2 2 = − 1 1 1 1 = − = − pV V V V ( =0 ) 2 2 2 2 = − − = p V V V V ( = 0 )
U and in the throttling process the sum of work W=1+2=B1-P22 the en C2-1=n11-n2V2 C2+P2V2=C1+P1V1 、= 2 Throttling process is const -enthalpy process It is isenthalpic 4上一内容下一内容令回主目录 返回 2021/2/21
上一内容 下一内容 回主目录 返回 2021/2/21 U and H in the throttling process the sum of work: W W W pV p V = + = − 1 2 1 1 2 2 then U U pV p V 2 1 1 1 2 2 − = − Throttling process is const.-enthalpy process! H H 2 1 = U p V U pV 2 2 2 1 1 1 + = + It is isenthalpic