2 f: let dislocation climb a distance dS b·1 f·dS"=-(x·A Jf b b tot
② fc : let dislocation climb a distance dS' S A b f S x A = − d 1 d ( ) c c c f b c = − x ③ f tot 2 c 2 tot s f = f + f b dS ⊥
3. Force on mixed dislocation B C X given: D a mixed dislocation AB of unit length with b//OX (AB,b=I-a determine: force on AB for slip and climb
3. Force on mixed dislocation given: D a mixed dislocation of unit length with AB b // OX ( , = −) AB b determine: force on for slip and climb AB x y z B A s f b v
Solution ①f f s=ob L x b directs to that part of crystal which contains extra-half plane I x directs to that part of crystal which moves along b b
Solution： ① f s : f s =b directs to that part of crystal which contains extra-half plane. L b directs to that part of crystal which moves along . l v f s = xz b b
y A to determine fc, AB is B resolved into Ac and CB X For: CB, F=o bcos. For: AC F=-obsin a AB→AB AC→A fe=F+F2=b(tx cos a-ox sin a)
For : , ; For : , ② fc : x z y o b C A B C A B to determine fc , is resolved into and AB → AB AB AC CB CB F1 = xybcos AC F2 = − x bsin AC → AC ( cos sin ) f c = F1 + F2 = b xy − x