二、还原反应—Na(Li)/NH3iq e Reduction by Addition of an Electron,a Proton sodium in liquid ammonia 炔烃被还原成反式烯烃 此条件下双键不被还原 机理请自学 CH3 H CH CH3 Na or li CH3C=CHCH2C≡CcH3 CHaC=CHCh,C H NH3(iq) -Birch reduction of benzene Na or li CH3 Na or li CH3 NH3(liq), etoh NH3 (liq), EtOH
二、还原反应——Na(Li)/NH3 (liq) Reduction by Addition of an Electron, a Proton ---- sodium in liquid ammonia ——炔烃被还原成反式烯烃 ——此条件下双键不被还原 ——机理请自学 ——Birch Reduction of Benzene CH3 C=CHCH2 C C H3 CCH3 Na or Li N H3 ( liq ) CH3 C=CHCH2 C C H3 H C H3 H Na or Li NH3 ( liq ) , EtOH Na or Li NH3 ( liq ) , EtOH CH3 CH3
●与苯环共轭的双键可以被还原,而不与苯环 共轭的双键不能还原 Na or li Na or li NH3 (liq ) etoh NH3(iq), etoH 酮的双分子还原 ④○。o Na, NH3(liq) O N N 2 PhCPh 2 Ph-C-Ph Ph Phph OH OH H,O Ph Ph Phph
与苯环共轭的双键可以被还原，而不与苯环 共轭的双键不能还原 Na or Li NH3 ( liq ) , EtOH Na or Li NH3 ( liq ) , EtOH O PhCPh Na , NH3 (liq) 2 Na Ph C O Ph Na Na Ph O Ph O Ph 2 Ph H2O Ph OH Ph OH Ph Ph 酮的双分子还原