、分析计算 1.输出功率P P=Ul E 7最大功率 omax 2√2R2R L 16
16 二、分析计算 最大功率： L S C L S C S C o R U R U U P 2 1 2 2 2 max = = E om om om o o o R U I U P U I 2 2 1 2 2 = = = 1. 输出功率Po
2.管耗Pc u CEICI 刀0 dot SO O 0 R ∫0 u sin ot (U sc-Uom sin at 2兀 R R 4 2(U。C 2 P.=2P.= sc om R,(丌
17 2. 管耗PC ( ) ( ) ( ) ( ) = − = − = − = 4 1 sin sin 2 1 2 1 2 1 2 0 0 0 1 1 1 S C o m o m L L o m S C Om L o S C O C CE C U U U R d t R U t U U t d t R u U u P u i = = − 4 2 2 2 1 S C o m o m L C C U U U R P P