SOLUTION a We want to evaluate H 2 H d t d t The reactor(reaction) volume 0.62.0.75=0.2121m3
SOLUTION. ◼ We want to evaluate ◼ The reactor(reaction) volume dt O dn O V and r dt H dn H V r 2 1 2 2 1 2 − = − − = − 2 3 0 6 0 75 0 2121 4 . . . m π V = =
he reaction equation +-O →HO 2 molecularweight 2 16 108 The rate of H,O produced Akmal HO produced / s=108kg /s 6kmol/s 18
◼ the reaction equation ◼ The rate of H2O produced 2 16 108 2 2 2 1 2 molecularweight H + O → H O kmol s kg kmol H O produced s kg s 6 / 18 1 _ / 108 / 2 = =
The rate of h and o consumed H2 used 6 kmol /s O, used =3 kmol/s The rate of reaction 0.2121m·6kmol 2829×104 mo used (mof rocket).S akmal =1.415×104 mol used 02121m3 (mof rocket)S
◼ The rate of H2 and O2 consumed H2 used = 6 kmol/s O2 used = 3 kmol/s ◼ The rate of reaction (m of rocket) s mol used 1.415 10 s 3kmol 0.2121m 1 r (m of rocket) s mol used 2.829 10 s 6kmol 0.2121m 1 r 3 4 O 3 3 4 H 3 2 2 − = − = − = − =
EXAMPLE THE LIVING PERSON A human being (75kg consumes about 6000 k of food per day. Assume that the food is all glucose and that the overall reaction is C6H12O6+602→)6CO2+6H2O,-4H12816kJ (from air(breathed out) Find man's metabolic rate (the rate of living, loving, laughing) in terms of moles of oxygen used per m3 of person per second
EXAMPLE , THE LIVING PERSON ◼ A human being (75kg) consumes about 6000 kJ of food per day. Assume that the food is all glucose and that the overall reaction is C6H12O6 +6O2→6CO2+6H2O, -ΔHr =2816 kJ (from air) (breathed out) Find man’s metabolic rate (the rate of living, loving, laughing) in terms of moles of oxygen used per m3 of person per second
SOLUTTON We want to find person
SOLUTION. ◼ We want to find dt O dn O V r person 1 2 2 − = −