Traffic Channel Reverse Link Equation 业务信道反向链路均衡 Eb/l4 at the bts receiver(BTS接收机的E/t): E P/Rb N +(+L/W P/R +1.,HAF:1+m1m VaF Voice activity Factor(typically 0. 4 to 0.5) VAF=话音激活因子(通常为04到05) Assume(假设) perfect power control(完全功率控制) ·Eb/l1=T, Isc =(N-1)P Solve for p(解答Pn) CDMA Technology and Side《# Telstra Operations for Unicom Senior CDMA Radio Design Principles Telstra 2001 Managers Telstra in confidence Making life easier
Advanced Learning Solutions Slide No. 6 Slide ‹#› Telstra © 2001 Telstra in confidence CDMA Technology and Operations for Unicom Senior Managers CDMA Radio Design Principles Traffic Channel Reverse Link Equation 业务信道反向链路均衡 Eb/It at the BTS receiver（BTS 接收机的 Eb/It ）： ( ) W I I N I VAF P R N I I W P R I E s c o c o s c r x b o s c o c r x b t b 1 / / / / + + = + + = VAF = Voice Activity Factor (typically 0.4 to 0.5) VAF = 话音激活因子 (通常为 0.4 到 0.5) Assume （假设） • perfect power control （完全功率控制） • Eb/It = G, • Isc = (Nu -1)Prx Solve for Prx （解答 Prx）
Reverse Link Equation反向链路均衡 Received full- rate Power per user: 每个用户接收到的全速率功率: F·NW W/R-TVAF (N2-1) W/R= spreading ratio(128 for evrc)W/R=扩展比率(128 for evrc) I= required eb/N。(typ.7dB)(I=要求的Eb/N(typ.7dB) N= number of simultaneous users(Nu=同时作用的用户数量) VAF mean voice activity factor(typ 0.45 VAF=平均话音激活因子(通常为045 N。W= total equivalent noise at the bts(N。W=BTS上等价噪声的总和) CDMA Technology and Side《# Telstra Operations for Unicom Senior CDMA Radio Design Principles Telstra 2001 Managers Telstra in confidence Making life easier
Advanced Learning Solutions Slide No. 7 Slide ‹#› Telstra © 2001 Telstra in confidence CDMA Technology and Operations for Unicom Senior Managers CDMA Radio Design Principles Reverse Link Equation 反向链路均衡 Received full-rate Power per user: 每个用户接收到的全速率功率： •W/R = spreading ratio (128 for EVRC) W/R = 扩展比率 (128 for EVRC) •F = Isc/(Isc+Ioc) •G= required Eb /No (typ. 7 dB) （ G = 要求的 Eb /No (typ. 7 dB)) •Nu = number of simultaneous users (Nu =同时作用的用户数量) •VAF = mean voice activity factor (typ 0.45) VAF = 平均话音激活因子 (通常为 0.45) •NoW = total equivalent noise at the BTS (NoW = BTS 上等价噪声的总和) ( −1) G − G = u o r x N F VAF W R N W P
Reverse Link Interference 反向链路干扰 Reverse link interference comes from in -cell F and out-of-cell mobiles +1 来自于进小区和出小区移动台的反向链路 SC 干扰 In-cell mobiles are power controlled by the BTS 进小区移 动台由BTS进行功率控制 Out-of-cell mobiles are power controlled by other bts 出小区移动台由其他BTS进行功率控制 nterference comes from a large number of distributed mobiles 干扰来自于许多分布式移动台 CDMA Technology and Side《# CDMA Radio Design Principles Telstra 2001 Telstra Operations for Unicom Senior Managers Telstra in confidence Making life easier
Advanced Learning Solutions Slide No. 8 Slide ‹#› Telstra © 2001 Telstra in confidence CDMA Technology and Operations for Unicom Senior Managers CDMA Radio Design Principles Reverse Link Interference 反向链路干扰 Ioc I sc • Reverse link interference comes from in-cell and out-of-cell mobiles 来自于进小区和出小区移动台的反向链路 干扰 • In-cell mobiles are power controlled by the BTS 进小区移 动台由BTS 进行功率控制 • Out-of-cell mobiles are power controlled by other BTS 出小区移动台由其他BTS进行功率控制 • Interference comes from a large number of distributed mobiles 干扰来自于许多分布式移动台 sc oc sc I I I F + =
Total Receive power 总接收功率 Total Receive power includes in-cell and out-of-cell interference, plus thermal noise 总接收功率包括进小区和出小区干扰,加上热噪声 total NW+1+ =NW+/F F·VAF·N./F NW1+ 等式1 W/R F·VAF·(Nn 噪声增益 CDMA Technology and Side《# Operations for Unicom Senior CDMA Radio Design Principles Telstra 2001 Telstra Managers Telstra in confidence Making life easier
Advanced Learning Solutions Slide No. 9 Slide ‹#› Telstra © 2001 Telstra in confidence CDMA Technology and Operations for Unicom Senior Managers CDMA Radio Design Principles Total Receive Power 总接收功率 Total Receive power includes in-cell and out-of-cell interference, plus thermal noise 总接收功率包括进小区和出小区干扰， 加上热噪声 G − − G = + = + = + + F VAF N W R VAF N F N W N W I F P N W I I u u o o s c o s c o c total r x ( 1) / 1 / Noise Rise 噪声增益 等式 1
Example 实例 Assume(假设): F=066,VAF=04,W/R=128 W=1.25 MHZ, R=9.6 kbps NoW=ktb FBts =-174 dBm/Hz +10log(1250000)+4 dB=-109 dBm -850 -90.0 Prx 950+101dBm Ptotal 100.0 9 7 d Bm g-1050 1101149 Reverse link -115.0 112.1 125.0 130.0 0 10 CDMA Technology and Side《# Telstra Operations for Unicom Senior CDMA Radio Design Principles Telstra 2001 Managers Telstra in confidence Making life easier
Advanced Learning Solutions Slide No. 10 Slide ‹#› Telstra © 2001 Telstra in confidence CDMA Technology and Operations for Unicom Senior Managers CDMA Radio Design Principles Example 实例 Assume （假设）： F = 0.66, VAF = 0.4, W/R = 128 W = 1.25 MHz, R = 9.6 kbps NoW = k T B FBTS = -174 dBm/Hz + 10log(1250000) + 4 dB = -109 dBm -114.9 -112.1 -97 dBm -101 dBm -130.0 -125.0 -120.0 -115.0 -110.0 -105.0 -100.0 -95.0 -90.0 -85.0 -80.0 0 10 20 30 40 50 N dBm Prx Ptotal