Sample problem 22-1 Calculate the vrms of Hat T=0f p=latn Under these conditions =8.99x10 kg/m Solution: 3P_3.01×10Pa) =1840m/s rs pV89×102kg/m
Sample problem 22-1 Calculate the of at , . Under these conditions . Solution: rms v T c = 0 P =1atm 2 3 H 8.99 10 k g / m − = m s k g m P Pa vrms 1840 / 8.99 10 / 3 3(1.01 10 ) 2 3 5 = = = H2
Sample problem 22-2 In Fig 22-2, L=10cm, P=latm, T=300K (a) How many moles of oxygen are in the box? fy (b) How many molecules Solution: (a)n= P(1.01×10°Pa)(0.10m) 0.041mol RT(8.31J/mo)(300k) X (b)N=nN4=(0.041m0)602×1023) 2.5×102 molecules
Sample problem 22-2 In Fig 22-2 , L=10cm, P=1atm, T=300K (a) How many moles of oxygen are in the box? (b) How many molecules ? Solution: (a) (b) mol J molk k Pa m RT PV n 0.041 (8.31 / )(300 ) (1.01 10 )(0.10 ) 5 3 = = = molecules N nN mol A 2 2 2 3 2.5 10 (0.041 )(6.02 10 ) = = = L L y x z m L A1