INTERNAL FORCESIN BENDING ③ Overhanging beam q— Uniformly distributed P一 Concentrated force force ●● ●● 5). Statically determinate and statically indeterminate beams Statically determinate beams: Reactions of the beam can be determined onl by static equilibrium equations, such as the above three kinds of basic beams indeterminate beams Reactions of the beam cannot be determined Statically or only part of reactions can be determined by static equilibrium equations 21
21 ③Overhanging beam — Concentrated force P q — Uniformly distributed force 5). Statically determinate and statically indeterminate beams Statically determinate beams：Reactions of the beam can be determined only by static equilibrium equations，such as the above three kinds of basic beams. Statically indeterminate beams： Reactions of the beam cannot be determined or only part of reactions can be determined by static equilibrium equations
意曲内为 ③外伸梁 q一均布力 P一集中力 ●● ●● 5.静定梁与超静定梁 静定梁:由静力学方程可求出支反力,如上述三种基本 形式的静定梁。 超静定梁:由静力学方程不可求出支反力或不能求出全 部支反力。 22
22 ③外伸梁 q — 均布力 P — 集中力 5. 静定梁与超静定梁 静定梁：由静力学方程可求出支反力，如上述三种基本 形式的静定梁。 超静定梁：由静力学方程不可求出支反力或不能求出全 部支反力
INTERNAL FORCESIN BENDING Example 1 A stock tank is shown in the figure. Its length is [=5m,its inside diameter is D=lm, thickness of its wall is t=10mm. Density of steel is 7.8g/cm. Density of the liquid is 1g/cm. Height of the liquid is 0.8m. Length of overhanging end is lm. Try to determine the calculation sketch of the stock tank Solution q- Unito rmly Distributed 平F ●● 0 23
23 Example 1 A stock tank is shown in the figure. Its length is L=5m，its inside diameter is D=1m，thickness of its wall is t =10mm. Density of steel is 7.8g/cm³. Density of the liquid is 1g/cm³. Height of the liquid is 0.8m. Length of overhanging end is 1m. Try to determine the calculation sketch of the stock tank. Solution： q — Uniformly Distributed force
意曲内为 [例1]贮液罐如图示,罐长L=5m,内径D=1m,壁厚t=10mm, 钢的密度为:78gcm,液体的密度为:1gm3,液面高 0.8m,外伸端长1m,试求贮液罐的计算简图。 解: q一均布力 ●● 0 24
24 [例1]贮液罐如图示，罐长L=5m，内径 D=1m，壁厚t =10mm， 钢的密度为： 7.8g/cm³，液体的密度为：1g/cm³ ,液面高 0.8m，外伸端长 1m，试求贮液罐的计算简图。 解： q — 均布力
INTERNAL FORCESIN BENDING q=2mg=x3=4g+447=4g+48 =IDty1g+[R-R(8-sin 0)ly,g 2 O=106.3=1855ad 0 =3.14×1×001×7800×98+[3.14×0.53 5×0.(1.855-m106.39)×100098 9-Uniformly Distributed =o(KM w) 平I ●●
25 L AL g A L g L V g L mg q 1 1 2 2 + = = = 106 3 1 855rad 0 = . = . Dt g R R g2 2 2 1 ( sin )] 2 1 = +[ − − = A1 1 g + A2 2 g = 9 (kN/m) 0.5 (1.855 sin106.3 )] 1000 9.8 2 1 3 14 1 0 01 7800 9 8 [3.14 0.5 2 2 − = . . . + − q — Uniformly Distributed force