82-5 Maximum power transfer in the dC case S R L RS+RI R PRL=I RI )2R1 Rs+RL B(pz),2(R、+R1)2-R1×2(Rs+Rn) R。-R 0 (R s+R) (Rs+R1)3 Equation is satisfied when Rl=r s. The maximum power is Pmax ARL
§2-5 Maximum power transfer in the DC case S L S L R R i + = L S L S RL L L R R R p i R 2 2 ( ) + = = 4 2 2 2 ( ) ( ) ( ) ( ) S L S L L S L RL S L R R R R R R R p dR d + + − + = Equation is satisfied when R L= R S . The maximum power is L S R P 4 2 max = 0 3 2 = + − = ( ) ( ) S L S L S R R R R
Example: What is the maximum power that can be delivered to an external load ri by the network 200 36 0.2A R Oc Solution:。=20×+u1=1.51u1=30(+0.2)1=24 40 36 40+0.2×30 20 +0.12 =0.2 ×30=2.4 20+3040 20+30 s2.4 0+0.12=0.18 Rm=36/0.18=200c2 36 162Ⅳ na 4×200
Example: What is the maximum power that can be delivered to an external load RL by the network. 1 1 1 1.5 40 20 oc = + = 0.2) 24V 40 30( 1 1 1 = + = oc = 36V 0 12 20 30 40 30 0 2 40 1 1 . = + . + = + sc i 30 2.4 20 30 20 1 0.2 = + = = + 0.12 = 0.18 = 36/ 0.18 = 200 40 2.4 s c Rt h i P 1.62W 4 200 362 max = = Solution: sc i oc
1 {R两端并何元件,使≠=0} 375 20 375 20 20 =0 50 50 3.75A 10 y3.75A
{ R 两端并何元件，使i=0} i
active Source controlled node pat loop reference branch clockwise counterclockwise
active source controlled node path loop reference branch clockwise counterclockwise
A mesh current may often be identified as abranch current, as i, and i, are identified above. This is not always true, however, for consideration of a square nine-mesh network soon shows that the central mesh current cannot be identified as the current in any branch
A mesh current may often be identified as abranch current,as i1 and i2 are identified above.This is not always true, however, for consideration of a square nine-mesh network soon shows that the central mesh current cannot be identified as the current in any branch