·The conducting intervals of the thyristors are120°Therefore, the rms current through thyristor:13.The conducting intervals of each phase are 240°Therefore, the rms AC input current2I. = I, = I.V3ia= iT1- iT4it = iT3 - iT6i= it5- iT2
•The conducting intervals of the thyristors are 120º. Therefore, the rms current through thyristor: •The conducting intervals of each phase are 240º. Therefore, the rms AC input current 3 T I = I d c d 2 I 3 I a = Ib = I = ia = iT 1 − iT4 ib= iT 3 − iT 6 ic = iT 5 − iT2
.Thefrequencyα =30 °Vdof the outputVabcbripple is six timesthe supplyfrequency.0al27yL sinotdot=1.35l cosα = o cosα2F(6-40)23
π 1 LL 2π+ π + d LL d0 α α=30° 0 ωt vd V = 2V sintdt =1.35V cos = V cos (6 − 40) 3 3 3 vab vcb vab vac vbc vba vca vcb •The frequency of the output ripple is six times the supply frequency
α =60 °VacVbeVbaVeaVebVabVab0wt12VL sinotdot=1.35l cosα = xo cosα(6-40)2
π 1 LL 2π+ π + d LL d0 0 ωt vd V = 2V sintdt =1.35V cos = V cos (6 − 40) 3 3 3 vab vac vbc vba vca α α=60° vcb vab