R: The squares correspond to the adjacent minterms are ad jacent squares Across the top and down the side of k-map, only one bit changes occur between ad jacent squares for each column and row 8: Logically adjacent 2 Adjacent C 00011110 04 28 Symmetrica 00 (0,8,24) 01 37 (13911) 51 26 410 o stack 10 MSB=A. LSB=D
The squares correspond to the adjacent minterms are adjacent squares. Across the top and down the side of k- map, only one bit changes occur between adjacent squares for each column and row Logically adjacent Adjacent Symmetrical (0,8,2,4) (1,3,9,11) stack 00 01 11 10 AB CD 00 01 11 10 0 4 12 8 1 5 13 9 3 7 15 11 2 6 14 10 MSB=A ; LSB=D
Describe a switching function K-map
Describe a switching function by K-map
F(ABCD)n(13512131415 CD00011110 图 Writing l in Th 28 00 square correspond 53 To a rrnrerrn 01 715 2614Ah0 10 MSB=A: LSB=D
F(A,B,C,D)=∑m(1,3,5,12,13,14,15) 00 01 11 10 AB CD 00 01 11 10 0 4 12 8 1 5 13 9 3 7 15 11 2 6 14 10 MSB=A ; LSB=D 1 1 1 1 1 1 1 Writing 1 in the square correspond to a minterm
剧F(ABCD)M(235710,111415) 0001110 图 Writing o in the 0 00 square correspond 139 01 50 o a axerol 1183070151 0 10 0 00 0 MSB=A. LSB=D
F(A,B,C,D)=∏M(2,3,5,7,10,11,14,15) 00 01 11 10 AB CD 00 01 11 10 0 4 12 8 1 5 13 9 3 7 15 11 2 6 14 10 MSB=A ; LSB=D 0 0 0 0 0 0 0 0 Writing 0 in the square correspond to a maxterm
Simplify a equation use N-Variable K-map
Simplify a equation use N-variable K-map