8.2.3 TemperatureEffectQpaA+bBdD+eEQpT2 =QpT1 +AHR +△H)T,AHRAHpPhysical enthalpyQaA+bBdD+eETAHR=Cnm.dTn,C,RKirchhoff EquationNn.C.dTAH,:pmP化学反应的热效应随温度变化，是由于生成物和反应物的物理烩随温度变化而引起的
8.2.3 Temperature Effect aA bB + aA bB + dD eE + dD eE + Qp 2 T2 Qp1 T1 HR HP Q Q H H PT PT R P 2 1 = + + 1 2 2 1 d d T R i pmi T R T P i pmi T P H n C T H n C T = = Kirchhoff Equation 化学反应的热效应随温度变化，是由于生成物和反应物的 物理焓随温度变化而引起的。 Physical enthalpy
8.2.3 Temperature EffectCpmi-Zn,Cmmi)dTn.C.>pmPRGenerally, the standard thermo-effect is knownThe thermo-effect at any temperature(En,Cpmi-En.Cpml)dTQ, =Q +298PR=Q+Z(H'r, -H298)-(H r, -H 298-pR
8.2.3 Temperature Effect Generally, the standard thermo-effect is known The thermo-effect at any temperature 2 2 2 0 298 0 ' ' ' ' 298 298 ( )d ( ) ( ) T p p i pmi i pmi P R p T T P R Q Q n C n C T Q H H H H = + − = + − − − 2 1 2 1 ( )d T p p i pmi i pmi T P R Q Q n C n C T = + −
8.3 Combustion Heat & Production HeatFuel +combustion supporting gases = products + heatAirOxygenTheoretical oxygen quantity: according to reaction equationTheoretical air quantity=4.76 × theoretical oxygen quantityIn practical combustions, the air is always excessiveactual airquantityexcessaircoefficent=theoretical airquantity
8.3 Combustion Heat & Production Heat Fuel +combustion supporting gases = products + heat Oxygen Air Theoretical oxygen quantity: according to reaction equation Theoretical air quantity=4.76× theoretical oxygen quantity In practical combustions, the air is always excessive actual air quantity excess air coefficent= theoretical air quantity
例某水煤气（干基）的体积组成如下：HO=0.003，CO=0.065，O,=0.002，CO=0.370，H,=0.500，CH4=0.005，N,=0.055，求1Nm3千基水煤气所需的理论空气量V。若α=1.15，实际空气量V为多少？烟气量为多少？解：写出各可燃成份的化学反应式：+(1)H,S+1.50,=H,0 +$0g+￥体积比11.51(2)CO + 0.50,= C02体积比10.514(3)H+ (0.50=H0#体积比10. 51#(4)CH4 +20,=C0+2H.0+21体积比12v理论氧气量为+V。=(1.5H,S+0.5CO+0.5H,+2CH4-O)+=1.5×0.003+0.5×0.370+0.5×0.500+2×0.005-0.002+= 0.4475 Nm*
理论空气量为100V.=4.762×0.4475=2.131Nm2221实际空气量为Va× = cV, = 1.15×2.131t=2.4506Nm*理论烟气量为：+V,=V,-V+(2H,S+CO+H, +3CH4 +CO, +N2)+=2.131-0.4475+(2×0.003+0.37+0.5+3×0.005+0.065+0.055)+=2.6945 Nm实际烟气量为+Vp=(α-1)V。+Vp=0.15×2.131+2.6945=3.0141Nm